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4.9x^2-5.14x-1=0
a = 4.9; b = -5.14; c = -1;
Δ = b2-4ac
Δ = -5.142-4·4.9·(-1)
Δ = 46.0196
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-5.14)-\sqrt{46.0196}}{2*4.9}=\frac{5.14-\sqrt{46.0196}}{9.8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-5.14)+\sqrt{46.0196}}{2*4.9}=\frac{5.14+\sqrt{46.0196}}{9.8} $
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